Sandbox 1A2: Difference between revisions
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Shown in the box to the right is an animation of the cyclization of D-glucose to form D-glucopyranose. The electron-withdrawing oxygen atom of the carbonyl group carries a permanent positive dipole while the alcohol group bound to the penultimate carbon acts as a nucleophile due to the two lone pairs of electrons around the oxygen atom. Listed below is an explanation of the animation broken down into two major steps. | Shown in the box to the right is an animation of the cyclization of D-glucose to form D-glucopyranose. The electron-withdrawing oxygen atom of the carbonyl group carries a permanent positive dipole while the alcohol group bound to the penultimate carbon acts as a nucleophile due to the two lone pairs of electrons around the oxygen atom. Listed below is an explanation of the animation broken down into two major steps. | ||
{{Template:Button Toggle Animation2}} may be used at any time to pause animation for a clearer view of the process. | {{Template:Button Toggle Animation2}} (This button may be used at any time to pause animation for a clearer view of the process.) | ||
Step 1 - Starting from its linear form, glucose begins to cyclize with the 90 degree rotation of the bond between C4 and C5. This causes the molecule to be "bent" in such a way that the C5 atom, or the penultimate carbon, is near the first carbon. The glucose molecule is now configured in a way that the "tail" of glucose (the penultimate carbon containing the alcohol) is close to the "head" of glucose (the carbon containing the aldehyde). | Step 1 - Starting from its linear form, glucose begins to cyclize with the 90 degree rotation of the bond between C4 and C5. This causes the molecule to be "bent" in such a way that the C5 atom, or the penultimate carbon, is near the first carbon. The glucose molecule is now configured in a way that the "tail" of glucose (the penultimate carbon containing the alcohol) is close to the "head" of glucose (the carbon containing the aldehyde). | ||