Cory Tiedeman Sandbox 1: Difference between revisions

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[[Image:mechanism.png|left|400px]]<ref>{{website2}}</ref>
[[Image:mechanism.png|left|400px]]<ref>{{website2}}</ref>
The   
The   
<scene name='Cory_Tiedeman_Sandbox_1/Active_site/1'>active site</scene> of enolase as shown, involves Lys 345, Lys 396, Glu 168, Glu 211, and His 159.  Enolase forms a complex with   
<scene name='Cory_Tiedeman_Sandbox_1/Active_site/1'>active site</scene> of enolase as shown, involves Lys 345, Lys 396, Glu 168, Glu 211, and His 159.  Enolase forms a complex with two    
<scene name='Cory_Tiedeman_Sandbox_1/Mg/3'>Mg 2+</scene> at its active site.  The Mg 2+ then forms a bond with 2PG at the deprotonated carboxylic acid on the 1'C to connect it with enolase.  It also is connects to Glu 211 and Lys 345.  Glu 211 makes a hydrogen bond with the alcohol group on the 3'C.  Lys 345 deprotonates the 2'C and then the 2'C forms an alkene with the 1'C which then moves the electrons forming the ketone onto the oxygen making it have a negative charge.  The other oxygen, which already has a negative charge, then moves its electron to form a ketone with the 1'C.  The electrons that made up the alkene between the 1'C adn 2'C then moves to form an alkene between the 2'C and 3'C.  This breaks the bond with the alcohol on the 3'C which deprotonates Glu 211 on enolase to form H2O.  Then the new molecule is released from enolase as PEP.  PEP then goes on through another step in glycolysis to create pyruvate.   
<scene name='Cory_Tiedeman_Sandbox_1/Mg/3'>Mg 2+'s</scene> at its active site
The substrate, 2PG, binds to the two<scene name='Cory_Tiedeman_Sandbox_1/Mechanism/4'>Mg2+'s, Glu 211, and Lys 345</scene>.  The Mg 2+ then forms a bond at the deprotonated carboxylic acid on the 1'C to connect it with enolase.  It also is connects to Glu 211 and Lys 345.  Glu 211 makes a hydrogen bond with the alcohol group on the 3'C.  Lys 345 deprotonates the 2'C and then the 2'C forms an alkene with the 1'C which then moves the electrons forming the ketone onto the oxygen making it have a negative charge.  The other oxygen, which already has a negative charge, then moves its electron to form a ketone with the 1'C.  The electrons that made up the alkene between the 1'C adn 2'C then moves to form an alkene between the 2'C and 3'C.  This breaks the bond with the alcohol on the 3'C which deprotonates Glu 211 on enolase to form H2O.  Then the new molecule is released from enolase as PEP.  PEP then goes on through another step in glycolysis to create pyruvate.   


Fluoride ions inhibits glycolysis by forming a bond with Mg 2+ thus blocks the substrate (2PG) from binding to the active site of enolase.<ref>{{textbook |author=Voet, Donald; Voet, Judith C.; Pratt, Charlotte W.|title=Fundamentals of Biochemistry: Life at the Molecular Level|edition= 3|pages=500|}}</ref>   
Fluoride ions inhibits glycolysis by forming a bond with Mg 2+ thus blocks the substrate (2PG) from binding to the active site of enolase.<ref>{{textbook |author=Voet, Donald; Voet, Judith C.; Pratt, Charlotte W.|title=Fundamentals of Biochemistry: Life at the Molecular Level|edition= 3|pages=500|}}</ref>   

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Cory Tiedeman, David Canner